The Bisectors of any Two Consecutive Angles of a Parallelogram Intersect at Right Angle
The Bisectors of any Two Consecutive Angles of a Parallelogram Intersect at Right Angle
| The Bisectors of Any Two Consecutive Angles Intersect at Right Angle: We know that parallelogram is a quadrilateral in which both the opposite pair of sides are parallel and equal to each other, The bisectors of any two consecutive angles intersect at right angle. | |
Theorem 5: In a parallelogram, the bisectors of any two consecutive angles intersect at right angle. GIVEN A parallelogram ABCD such that the bisectors of consecutive angles A and B intersect at P. To prove <APB = 90 Proof Since ABCD is a parallelogram. Therefore, AD Now, AD
In <1 + <APB + <2 = 180
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| ILLUSTRATION: In the given figure, AP and BP are the bisectors of | |
Solution: In a parallelogram the angle bisectors of a parallelogram meet at right angles.
As ABCD is a parallelogram. Therefore, AD Now, AD
Hence Proved |  |
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